Camera TransformΒΆ

We can see the camera frame and the world frame. There is a grid of points from which we know the world coordinates. If we know the location and orientation of the camera in the world, we can easily compute the location of the points on the image.

Camera and world frames, Camera image
print(__doc__)


import numpy as np
import matplotlib.pyplot as plt
from pytransform3d.plot_utils import make_3d_axis
from pytransform3d.rotations import active_matrix_from_intrinsic_euler_xyz
from pytransform3d.transformations import transform_from, plot_transform
from pytransform3d.camera import make_world_grid, world2image, plot_camera


cam2world = transform_from(
    active_matrix_from_intrinsic_euler_xyz([-np.pi + 1, -0.1, 0.3]),
    [0.2, -1, 0.5])
focal_length = 0.0036
sensor_size = (0.00367, 0.00274)
image_size = (640, 480)
intrinsic_camera_matrix = np.array([
    [focal_length, 0, sensor_size[0] / 2],
    [0, focal_length, sensor_size[1] / 2],
    [0, 0, 1]
])

world_grid = make_world_grid(n_points_per_line=101)
image_grid = world2image(world_grid, cam2world, sensor_size, image_size,
                         focal_length, kappa=0.4)

plt.figure(figsize=(12, 5))
ax = make_3d_axis(1, 121, unit="m")
ax.view_init(elev=30, azim=-70)
plot_transform(ax)
plot_transform(ax, A2B=cam2world, s=0.3, name="Camera")
plot_camera(ax, intrinsic_camera_matrix, cam2world,
            sensor_size=sensor_size, virtual_image_distance=0.5)
ax.set_title("Camera and world frames")
ax.scatter(
    world_grid[:, 0], world_grid[:, 1], world_grid[:, 2], s=1, alpha=0.2)
ax.scatter(world_grid[-1, 0], world_grid[-1, 1], world_grid[-1, 2], color="r")
ax.view_init(elev=25, azim=-130)

ax = plt.subplot(122, aspect="equal")
ax.set_title("Camera image")
ax.set_xlim(0, image_size[0])
ax.set_ylim(0, image_size[1])
ax.scatter(image_grid[:, 0], -(image_grid[:, 1] - image_size[1]))
ax.scatter(image_grid[-1, 0], -(image_grid[-1, 1] - image_size[1]), color="r")

plt.show()

Total running time of the script: ( 0 minutes 0.260 seconds)

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